C++中的函数重载
在同一个作用域中,可以为同一个函数名具有多个定义。函数的定义必须在参数列表中的参数类型和/或数量上彼此不同。您不能重载仅在返回类型上有所不同的函数声明。以下是使用相同函数print()打印不同数据类型的示例-
#include <iostream>
using namespace std;
class Distance {
private:
int feet; // 0 to infinite
int inches; // 0 to 12
public:
// required constructors
Distance() {
feet = 0;
inches = 0;
}
Distance(int f, int i) {
feet = f;
inches = i;
}
// method to display distance
void displayDistance() {
cout << "F: " << feet << " I:" << inches << endl;
}
// overloaded minus (-) operator
Distance operator- () {
feet = -feet;
inches = -inches;
return Distance(feet, inches);
}
// overloaded < operator
bool operator <(const Distance& d) {
if(feet < d.feet) {
return true;
}
if(feet == d.feet && inches < d.inches) {
return true;
}
return false;
}
};
int main() {
Distance D1(11, 10), D2(5, 11);
if( D1 < D2 ) {
cout << "D1 is less than D2 " << endl;
} else {
cout << "D2 is less than D1 " << endl;
}
return 0;
}
尝试一下
编译并执行上述代码后,将产生以下结果-