PHP Ajax搜索
搜索界面search.html
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<style>
span {
color: green;
}
</style>
<script>
function showHint(str) {
if (str.length == 0) {
document.getElementById("txtHint").innerHTML = "";
return;
}else {
var xmlhttp = new XMLHttpRequest();
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
}
}
xmlhttp.open("GET", "php_ajax.php?q=" + str, true);
xmlhttp.send();
}
}
</script>
</head>
<body>
<p><b>搜索您最喜欢的教程:</b></p>
<form>
<input type = "text" onkeyup = "showHint(this.value)">
</form>
<p>课程的名字: <span id="txtHint"></span></p>
</body>
</html>
上面的代码打开一个文件,名字叫做php_ajax.php,使用GET方法,所以我们需要创建一个文件,在同一目录中名为php_ajax.php的名称,将输出将id为txtHint的元素中。
处理脚本php_ajax.php
<?php
// 这些数据在真实的案例中 一般从数据库查询出来
$a[] = "Android";
$a[] = "B 语言";
$a[] = "C 语言";
$a[] = "D 语言";
$a[] = "euphoria";
$a[] = "F#";
$a[] = "GWT";
$a[] = "HTML5";
$a[] = "ibatis";
$a[] = "Java";
$a[] = "K 语言";
$a[] = "Lisp";
$a[] = "Microsoft technologies";
$a[] = "Networking";
$a[] = "Open Source";
$a[] = "Prototype";
$a[] = "QC";
$a[] = "Restful web services";
$a[] = "Scrum";
$a[] = "Testing";
$a[] = "UML";
$a[] = "VB Script";
$a[] = "Web Technologies";
$a[] = "Xerox Technology";
$a[] = "YQL";
$a[] = "ZOPL";
$q = $_REQUEST["q"];
$hint = "";
if ($q !== "") {
$q = strtolower($q);
$len = strlen($q);
foreach($a as $name) {
if (stristr($q, substr($name, 0, $len))) {
if ($hint === "") {
$hint = $name;
}else {
$hint .= ", $name";
}
}
}
}
echo $hint === "" ? "请你输入合法的教程名字" : $hint;
?>
搜索效果如下图所示